6u^2+5u-2=0

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Solution for 6u^2+5u-2=0 equation: 



6u^2+5u-2=0

a = 6; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·6·(-2)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{73}}{2*6}=\frac{-5-\sqrt{73}}{12}
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{73}}{2*6}=\frac{-5+\sqrt{73}}{12}
$

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